Base | Representation |
---|---|
bin | 101110100101000001… |
… | …101100001110110101 |
3 | 11210002111220010000020 |
4 | 232211001230032311 |
5 | 1304411402333323 |
6 | 34550435035353 |
7 | 3420243145566 |
oct | 564501541665 |
9 | 153074803006 |
10 | 50013324213 |
11 | 1a2352437a6 |
12 | 983943bb59 |
13 | 4940756688 |
14 | 25c63dc16d |
15 | 147ab27ae3 |
hex | ba506c3b5 |
50013324213 has 4 divisors (see below), whose sum is σ = 66684432288. Its totient is φ = 33342216140.
The previous prime is 50013324203. The next prime is 50013324241. The reversal of 50013324213 is 31242331005.
50013324213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50013324213 - 24 = 50013324197 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50013324203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8335554033 + ... + 8335554038.
It is an arithmetic number, because the mean of its divisors is an integer number (16671108072).
Almost surely, 250013324213 is an apocalyptic number.
It is an amenable number.
50013324213 is a deficient number, since it is larger than the sum of its proper divisors (16671108075).
50013324213 is a wasteful number, since it uses less digits than its factorization.
50013324213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16671108074.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 50013324213 its reverse (31242331005), we get a palindrome (81255655218).
The spelling of 50013324213 in words is "fifty billion, thirteen million, three hundred twenty-four thousand, two hundred thirteen".
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