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5001333214111 = 13384717939547
BaseRepresentation
bin100100011000111011010…
…1100001000101110011111
3122201010022111210102100121
41020301312230020232133
51123420212300322421
614345325235535411
71024222461615553
oct110616654105637
918633274712317
105001333214111
111659065240003
1268936045a567
132a381535b160
141340cc871863
158a1697c2d41
hex48c76b08b9f

5001333214111 has 4 divisors (see below), whose sum is σ = 5386051153672. Its totient is φ = 4616615274552.

The previous prime is 5001333214093. The next prime is 5001333214127. The reversal of 5001333214111 is 1114123331005.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5001333214111 - 213 = 5001333205919 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5001333214711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192358969761 + ... + 192358969786.

It is an arithmetic number, because the mean of its divisors is an integer number (1346512788418).

Almost surely, 25001333214111 is an apocalyptic number.

5001333214111 is a deficient number, since it is larger than the sum of its proper divisors (384717939561).

5001333214111 is a wasteful number, since it uses less digits than its factorization.

5001333214111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 384717939560.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 5001333214111 its reverse (1114123331005), we get a palindrome (6115456545116).

The spelling of 5001333214111 in words is "five trillion, one billion, three hundred thirty-three million, two hundred fourteen thousand, one hundred eleven".

Divisors: 1 13 384717939547 5001333214111