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500134224433 is a prime number
BaseRepresentation
bin1110100011100100101…
…00101010001000110001
31202210221012210000112211
413101302110222020301
531143233330140213
61021431500052121
751063535523254
oct7216224521061
91683835700484
10500134224433
11183118805288
1280b19b34041
1338215bb530c
141a2c6da309b
15d0227e853d
hex747252a231

500134224433 has 2 divisors, whose sum is σ = 500134224434. Its totient is φ = 500134224432.

The previous prime is 500134224413. The next prime is 500134224451. The reversal of 500134224433 is 334422431005.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 415376383009 + 84757841424 = 644497^2 + 291132^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-500134224433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 500134224395 and 500134224404.

It is not a weakly prime, because it can be changed into another prime (500134224413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250067112216 + 250067112217.

It is an arithmetic number, because the mean of its divisors is an integer number (250067112217).

Almost surely, 2500134224433 is an apocalyptic number.

It is an amenable number.

500134224433 is a deficient number, since it is larger than the sum of its proper divisors (1).

500134224433 is an equidigital number, since it uses as much as digits as its factorization.

500134224433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 500134224433 its reverse (334422431005), we get a palindrome (834556655438).

The spelling of 500134224433 in words is "five hundred billion, one hundred thirty-four million, two hundred twenty-four thousand, four hundred thirty-three".