Base | Representation |
---|---|
bin | 100100011001110011100… |
… | …1111000101010000011111 |
3 | 122201022012002210101012011 |
4 | 1020303213033011100133 |
5 | 1123433044141020020 |
6 | 14350240450452051 |
7 | 1024320330256255 |
oct | 110634717052037 |
9 | 18638162711164 |
10 | 5003221423135 |
11 | 1659944072431 |
12 | 6897a8894027 |
13 | 2a3a565c3bc0 |
14 | 13422b54a5d5 |
15 | 8a22a45235a |
hex | 48ce73c541f |
5003221423135 has 32 divisors (see below), whose sum is σ = 6477602503680. Its totient is φ = 3687889715328.
The previous prime is 5003221423103. The next prime is 5003221423157. The reversal of 5003221423135 is 5313241223005.
5003221423135 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5003221423135 - 25 = 5003221423103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5003221423097 and 5003221423106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 145921704 + ... + 145955986.
It is an arithmetic number, because the mean of its divisors is an integer number (202425078240).
Almost surely, 25003221423135 is an apocalyptic number.
5003221423135 is a deficient number, since it is larger than the sum of its proper divisors (1474381080545).
5003221423135 is a wasteful number, since it uses less digits than its factorization.
5003221423135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38367.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 5003221423135 in words is "five trillion, three billion, two hundred twenty-one million, four hundred twenty-three thousand, one hundred thirty-five".
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