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500412512031 = 3166804170677
BaseRepresentation
bin1110100100000101110…
…10001111011100011111
31202211122121102111100220
413102002322033130133
531144321100341111
61021515240452423
751103455112335
oct7220272173437
91684577374326
10500412512031
111832508a9933
1280b9717a113
133825b750433
141a311d23b55
15d03be68e06
hex7482e8f71f

500412512031 has 4 divisors (see below), whose sum is σ = 667216682712. Its totient is φ = 333608341352.

The previous prime is 500412512011. The next prime is 500412512063. The reversal of 500412512031 is 130215214005.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 500412512031 - 27 = 500412511903 is a prime.

It is a super-2 number, since 2×5004125120312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 500412511992 and 500412512010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (500412512011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83402085336 + ... + 83402085341.

It is an arithmetic number, because the mean of its divisors is an integer number (166804170678).

Almost surely, 2500412512031 is an apocalyptic number.

500412512031 is a deficient number, since it is larger than the sum of its proper divisors (166804170681).

500412512031 is a wasteful number, since it uses less digits than its factorization.

500412512031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166804170680.

The product of its (nonzero) digits is 1200, while the sum is 24.

Adding to 500412512031 its reverse (130215214005), we get a palindrome (630627726036).

The spelling of 500412512031 in words is "five hundred billion, four hundred twelve million, five hundred twelve thousand, thirty-one".

Divisors: 1 3 166804170677 500412512031