Base | Representation |
---|---|
bin | 101110100111010010… |
… | …011000110000110001 |
3 | 11210012011021012201222 |
4 | 232213102120300301 |
5 | 1310001110132340 |
6 | 34554312034425 |
7 | 3421213436150 |
oct | 564722306061 |
9 | 153164235658 |
10 | 50051255345 |
11 | 1a2546a0a43 |
12 | 984a092a15 |
13 | 4948577630 |
14 | 25cb473597 |
15 | 147e11b8b5 |
hex | ba7498c31 |
50051255345 has 16 divisors (see below), whose sum is σ = 73921854720. Its totient is φ = 31680794304.
The previous prime is 50051255329. The next prime is 50051255357. The reversal of 50051255345 is 54355215005.
It is a cyclic number.
It is not a de Polignac number, because 50051255345 - 24 = 50051255329 is a prime.
It is a super-3 number, since 3×500512553453 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55000925 + ... + 55001834.
It is an arithmetic number, because the mean of its divisors is an integer number (4620115920).
Almost surely, 250051255345 is an apocalyptic number.
It is an amenable number.
50051255345 is a deficient number, since it is larger than the sum of its proper divisors (23870599375).
50051255345 is a wasteful number, since it uses less digits than its factorization.
50051255345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110002784.
The product of its (nonzero) digits is 75000, while the sum is 35.
The spelling of 50051255345 in words is "fifty billion, fifty-one million, two hundred fifty-five thousand, three hundred forty-five".
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