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50062402545439 is a prime number
BaseRepresentation
bin10110110001000000011111…
…01110000110011100011111
320120020220210220120000122111
423120200033232012130133
523030210300022423224
6254250203352254451
713354614001333354
oct1330401756063437
9216226726500574
1050062402545439
1114a51389127099
1257465193a1427
1321c1b30b4a58b
14c510671c062b
155bc38828cd94
hex2d880fb8671f

50062402545439 has 2 divisors, whose sum is σ = 50062402545440. Its totient is φ = 50062402545438.

The previous prime is 50062402545437. The next prime is 50062402545487. The reversal of 50062402545439 is 93454520426005.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50062402545439 - 21 = 50062402545437 is a prime.

It is a super-3 number, since 3×500624025454393 (a number of 42 digits) contains 333 as substring.

Together with 50062402545437, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 50062402545392 and 50062402545401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50062402545437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25031201272719 + 25031201272720.

It is an arithmetic number, because the mean of its divisors is an integer number (25031201272720).

Almost surely, 250062402545439 is an apocalyptic number.

50062402545439 is a deficient number, since it is larger than the sum of its proper divisors (1).

50062402545439 is an equidigital number, since it uses as much as digits as its factorization.

50062402545439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184000, while the sum is 49.

The spelling of 50062402545439 in words is "fifty trillion, sixty-two billion, four hundred two million, five hundred forty-five thousand, four hundred thirty-nine".