Base | Representation |
---|---|
bin | 101110101001001110… |
… | …011111001000110101 |
3 | 11210021102111000012211 |
4 | 232221032133020311 |
5 | 1310032422143232 |
6 | 35001433213421 |
7 | 3422060111434 |
oct | 565116371065 |
9 | 153242430184 |
10 | 50083787317 |
11 | 1a270aa0773 |
12 | 9858b61271 |
13 | 4952227c15 |
14 | 25d190111b |
15 | 1481de5a47 |
hex | ba939f235 |
50083787317 has 4 divisors (see below), whose sum is σ = 50084580736. Its totient is φ = 50082993900.
The previous prime is 50083787293. The next prime is 50083787323. The reversal of 50083787317 is 71378738005.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50083787317 - 219 = 50083263029 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50083787357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292983 + ... + 431284.
It is an arithmetic number, because the mean of its divisors is an integer number (12521145184).
Almost surely, 250083787317 is an apocalyptic number.
It is an amenable number.
50083787317 is a deficient number, since it is larger than the sum of its proper divisors (793419).
50083787317 is an equidigital number, since it uses as much as digits as its factorization.
50083787317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 793418.
The product of its (nonzero) digits is 987840, while the sum is 49.
The spelling of 50083787317 in words is "fifty billion, eighty-three million, seven hundred eighty-seven thousand, three hundred seventeen".
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