Base | Representation |
---|---|
bin | 101110101010010100… |
… | …000101101011011001 |
3 | 11210022200210222202001 |
4 | 232222110011223121 |
5 | 1310102110024423 |
6 | 35003324241001 |
7 | 3422401153246 |
oct | 565224055331 |
9 | 153280728661 |
10 | 50102033113 |
11 | 1a280323040 |
12 | 98630a0161 |
13 | 4955c45a52 |
14 | 25d40d05cd |
15 | 14837ebcad |
hex | baa505ad9 |
50102033113 has 8 divisors (see below), whose sum is σ = 55472536800. Its totient is φ = 44867491680.
The previous prime is 50102033083. The next prime is 50102033161. The reversal of 50102033113 is 31133020105.
50102033113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 50102033113 - 25 = 50102033081 is a prime.
It is a super-2 number, since 2×501020331132 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50102033183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33989788 + ... + 33991261.
It is an arithmetic number, because the mean of its divisors is an integer number (6934067100).
Almost surely, 250102033113 is an apocalyptic number.
It is an amenable number.
50102033113 is a deficient number, since it is larger than the sum of its proper divisors (5370503687).
50102033113 is a wasteful number, since it uses less digits than its factorization.
50102033113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67981127.
The product of its (nonzero) digits is 270, while the sum is 19.
Adding to 50102033113 its reverse (31133020105), we get a palindrome (81235053218).
The spelling of 50102033113 in words is "fifty billion, one hundred two million, thirty-three thousand, one hundred thirteen".
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