Base | Representation |
---|---|
bin | 101110101010011111… |
… | …010011010010110111 |
3 | 11210022220100022210011 |
4 | 232222133103102313 |
5 | 1310103333104341 |
6 | 35003511241051 |
7 | 3422435144641 |
oct | 565237232267 |
9 | 153286308704 |
10 | 50104972471 |
11 | 1a281a50464 |
12 | 9864079187 |
13 | 4956734908 |
14 | 25d4657891 |
15 | 1483bccb81 |
hex | baa7d34b7 |
50104972471 has 2 divisors, whose sum is σ = 50104972472. Its totient is φ = 50104972470.
The previous prime is 50104972469. The next prime is 50104972499. The reversal of 50104972471 is 17427940105.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50104972471 - 21 = 50104972469 is a prime.
It is a super-3 number, since 3×501049724713 (a number of 33 digits) contains 333 as substring.
Together with 50104972469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50104972441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25052486235 + 25052486236.
It is an arithmetic number, because the mean of its divisors is an integer number (25052486236).
Almost surely, 250104972471 is an apocalyptic number.
50104972471 is a deficient number, since it is larger than the sum of its proper divisors (1).
50104972471 is an equidigital number, since it uses as much as digits as its factorization.
50104972471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70560, while the sum is 40.
The spelling of 50104972471 in words is "fifty billion, one hundred four million, nine hundred seventy-two thousand, four hundred seventy-one".
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