Base | Representation |
---|---|
bin | 101110101010110011… |
… | …100001100111100111 |
3 | 11210100021022200010221 |
4 | 232222303201213213 |
5 | 1310111212232043 |
6 | 35004221025211 |
7 | 3422531205235 |
oct | 565263414747 |
9 | 153307280127 |
10 | 50110274023 |
11 | 1a284a41607 |
12 | 98659b5207 |
13 | 495786ca24 |
14 | 25d5237955 |
15 | 14843c88ed |
hex | baace19e7 |
50110274023 has 4 divisors (see below), whose sum is σ = 50161251888. Its totient is φ = 50059296160.
The previous prime is 50110273963. The next prime is 50110274051. The reversal of 50110274023 is 32047201105.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50110274023 - 233 = 41520339431 is a prime.
It is a super-2 number, since 2×501102740232 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50110274063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25487458 + ... + 25489423.
It is an arithmetic number, because the mean of its divisors is an integer number (12540312972).
Almost surely, 250110274023 is an apocalyptic number.
50110274023 is a deficient number, since it is larger than the sum of its proper divisors (50977865).
50110274023 is an equidigital number, since it uses as much as digits as its factorization.
50110274023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50977864.
The product of its (nonzero) digits is 1680, while the sum is 25.
Adding to 50110274023 its reverse (32047201105), we get a palindrome (82157475128).
The spelling of 50110274023 in words is "fifty billion, one hundred ten million, two hundred seventy-four thousand, twenty-three".
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