Base | Representation |
---|---|
bin | 100100011101011100111… |
… | …0110111100101000001011 |
3 | 122202001101200202010212001 |
4 | 1020322321312330220023 |
5 | 1124100112303244303 |
6 | 14354013345331431 |
7 | 1025015330455342 |
oct | 110727166745013 |
9 | 18661350663761 |
10 | 5011050056203 |
11 | 16621a1134314 |
12 | 68b212636b77 |
13 | 2a4703496769 |
14 | 134771166b59 |
15 | 8a53789c31d |
hex | 48eb9dbca0b |
5011050056203 has 2 divisors, whose sum is σ = 5011050056204. Its totient is φ = 5011050056202.
The previous prime is 5011050056107. The next prime is 5011050056237. The reversal of 5011050056203 is 3026500501105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5011050056203 - 29 = 5011050055691 is a prime.
It is a super-3 number, since 3×50110500562033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5011050056263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505525028101 + 2505525028102.
It is an arithmetic number, because the mean of its divisors is an integer number (2505525028102).
Almost surely, 25011050056203 is an apocalyptic number.
5011050056203 is a deficient number, since it is larger than the sum of its proper divisors (1).
5011050056203 is an equidigital number, since it uses as much as digits as its factorization.
5011050056203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 5011050056203 its reverse (3026500501105), we get a palindrome (8037550557308).
The spelling of 5011050056203 in words is "five trillion, eleven billion, fifty million, fifty-six thousand, two hundred three".
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