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5011331512391 is a prime number
BaseRepresentation
bin100100011101100101010…
…1000100111100001000111
3122202002010022100121011022
41020323022220213201013
51124101201331344031
614354101322101355
71025025316012331
oct110731250474107
918662108317138
105011331512391
111662325aa2536
1268b29094a85b
132a47498a0b99
1413479a6b0451
158a55244697b
hex48ecaa27847

5011331512391 has 2 divisors, whose sum is σ = 5011331512392. Its totient is φ = 5011331512390.

The previous prime is 5011331512381. The next prime is 5011331512457. The reversal of 5011331512391 is 1932151331105.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5011331512391 is a prime.

It is a super-2 number, since 2×50113315123912 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5011331512381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505665756195 + 2505665756196.

It is an arithmetic number, because the mean of its divisors is an integer number (2505665756196).

Almost surely, 25011331512391 is an apocalyptic number.

5011331512391 is a deficient number, since it is larger than the sum of its proper divisors (1).

5011331512391 is an equidigital number, since it uses as much as digits as its factorization.

5011331512391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12150, while the sum is 35.

Adding to 5011331512391 its reverse (1932151331105), we get a palindrome (6943482843496).

The spelling of 5011331512391 in words is "five trillion, eleven billion, three hundred thirty-one million, five hundred twelve thousand, three hundred ninety-one".