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50113997 is a prime number
BaseRepresentation
bin1011111100101…
…0110111001101
310111022001110222
42333022313031
5100312121442
64550041125
71145650643
oct277126715
9114261428
1050113997
112631942a
12149491a5
13a4c826b
146927193
1545ed8d2
hex2fcadcd

50113997 has 2 divisors, whose sum is σ = 50113998. Its totient is φ = 50113996.

The previous prime is 50113993. The next prime is 50114017. The reversal of 50113997 is 79931105.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48846121 + 1267876 = 6989^2 + 1126^2 .

It is a cyclic number.

It is not a de Polignac number, because 50113997 - 22 = 50113993 is a prime.

It is a super-2 number, since 2×501139972 = 5022825390632018, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50113993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25056998 + 25056999.

It is an arithmetic number, because the mean of its divisors is an integer number (25056999).

Almost surely, 250113997 is an apocalyptic number.

It is an amenable number.

50113997 is a deficient number, since it is larger than the sum of its proper divisors (1).

50113997 is an equidigital number, since it uses as much as digits as its factorization.

50113997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8505, while the sum is 35.

The square root of 50113997 is about 7079.1240277311. The cubic root of 50113997 is about 368.6829163805.

The spelling of 50113997 in words is "fifty million, one hundred thirteen thousand, nine hundred ninety-seven".