50114126533 has 4 divisors (see below), whose sum is σ = 52751712160. Its totient is φ = 47476540908.

The previous prime is 50114126501. The next prime is 50114126563. The reversal of 50114126533 is 33562141105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50114126533 - 2⁵ = 50114126501 is a prime.

It is a super-2 number, since 2×50114126533² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50114126495 and 50114126504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50114126563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1318792785 + ... + 1318792822.

It is an arithmetic number, because the mean of its divisors is an integer number (13187928040).

Almost surely, 2^50114126533 is an apocalyptic number.

It is an amenable number.

50114126533 is a deficient number, since it is larger than the sum of its proper divisors (2637585627).

50114126533 is a wasteful number, since it uses less digits than its factorization.

50114126533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2637585626.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 50114126533 its reverse (33562141105), we get a palindrome (83676267638).

The spelling of 50114126533 in words is "fifty billion, one hundred fourteen million, one hundred twenty-six thousand, five hundred thirty-three".