Base | Representation |
---|---|
bin | 101110101011100000… |
… | …100000010011001111 |
3 | 11210101002111201110121 |
4 | 232223200200103033 |
5 | 1310122222040403 |
6 | 35005321445411 |
7 | 3423033344455 |
oct | 565340402317 |
9 | 153332451417 |
10 | 50122065103 |
11 | 1a290665400 |
12 | 9869940867 |
13 | 495a13a8b6 |
14 | 25d6a269d5 |
15 | 14854573bd |
hex | bab8204cf |
50122065103 has 12 divisors (see below), whose sum is σ = 56374083304. Its totient is φ = 44505846000.
The previous prime is 50122065089. The next prime is 50122065127. The reversal of 50122065103 is 30156022105.
It is not a de Polignac number, because 50122065103 - 233 = 41532130511 is a prime.
It is a super-3 number, since 3×501220651033 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50122065173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4811448 + ... + 4821853.
Almost surely, 250122065103 is an apocalyptic number.
50122065103 is a deficient number, since it is larger than the sum of its proper divisors (6252018201).
50122065103 is a wasteful number, since it uses less digits than its factorization.
50122065103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9633366 (or 9633355 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 50122065103 its reverse (30156022105), we get a palindrome (80278087208).
The spelling of 50122065103 in words is "fifty billion, one hundred twenty-two million, sixty-five thousand, one hundred three".
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