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5013220307 is a prime number
BaseRepresentation
bin1001010101100111…
…11010101111010011
3110221101020222102012
410222303322233103
540231341022212
62145242413135
7235142445434
oct45263725723
913841228365
105013220307
112142917687
12b7ab011ab
1361b80a164
14357b4348b
151e51b8922
hex12acfabd3

5013220307 has 2 divisors, whose sum is σ = 5013220308. Its totient is φ = 5013220306.

The previous prime is 5013220301. The next prime is 5013220309. The reversal of 5013220307 is 7030223105.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5013220307 - 212 = 5013216211 is a prime.

Together with 5013220309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5013220301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506610153 + 2506610154.

It is an arithmetic number, because the mean of its divisors is an integer number (2506610154).

Almost surely, 25013220307 is an apocalyptic number.

5013220307 is a deficient number, since it is larger than the sum of its proper divisors (1).

5013220307 is an equidigital number, since it uses as much as digits as its factorization.

5013220307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 23.

The square root of 5013220307 is about 70804.0980946725. The cubic root of 5013220307 is about 1711.4817141401.

The spelling of 5013220307 in words is "five billion, thirteen million, two hundred twenty thousand, three hundred seven".