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50132342551 = 223672241353
BaseRepresentation
bin101110101100000111…
…101101011100010111
311210101210211212110211
4232230013231130113
51310132334430201
635010330030251
73423216611044
oct565407553427
9153353755424
1050132342551
111a296444a65
129871278387
13495c2c8825
1425d81401cb
1514862d7651
hexbac1ed717

50132342551 has 4 divisors (see below), whose sum is σ = 50134606272. Its totient is φ = 50130078832.

The previous prime is 50132342497. The next prime is 50132342569. The reversal of 50132342551 is 15524323105.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50132342551 - 219 = 50131818263 is a prime.

It is a super-3 number, since 3×501323425513 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50132342581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1098310 + ... + 1143043.

It is an arithmetic number, because the mean of its divisors is an integer number (12533651568).

Almost surely, 250132342551 is an apocalyptic number.

50132342551 is a deficient number, since it is larger than the sum of its proper divisors (2263721).

50132342551 is a wasteful number, since it uses less digits than its factorization.

50132342551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2263720.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 50132342551 its reverse (15524323105), we get a palindrome (65656665656).

The spelling of 50132342551 in words is "fifty billion, one hundred thirty-two million, three hundred forty-two thousand, five hundred fifty-one".

Divisors: 1 22367 2241353 50132342551