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50142342031 is a prime number
BaseRepresentation
bin101110101100101101…
…110110101110001111
311210102111122220011221
4232230231312232033
51310142414421111
635011324224211
73423400606045
oct565455665617
9153374586157
1050142342031
111a2a10547a1
12987469b067
1349613ba092
1425d95c4395
151487110371
hexbacb76b8f

50142342031 has 2 divisors, whose sum is σ = 50142342032. Its totient is φ = 50142342030.

The previous prime is 50142342001. The next prime is 50142342079. The reversal of 50142342031 is 13024324105.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50142342031 - 27 = 50142341903 is a prime.

It is a super-2 number, since 2×501423420312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50142341987 and 50142342005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50142342001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25071171015 + 25071171016.

It is an arithmetic number, because the mean of its divisors is an integer number (25071171016).

Almost surely, 250142342031 is an apocalyptic number.

50142342031 is a deficient number, since it is larger than the sum of its proper divisors (1).

50142342031 is an equidigital number, since it uses as much as digits as its factorization.

50142342031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 50142342031 its reverse (13024324105), we get a palindrome (63166666136).

The spelling of 50142342031 in words is "fifty billion, one hundred forty-two million, three hundred forty-two thousand, thirty-one".