Base | Representation |
---|---|
bin | 10110110011010101111000… |
… | …00011011100110010010010 |
3 | 20120112120211020022011012210 |
4 | 23121222330003130302102 |
5 | 23033014022412000300 |
6 | 254351105515332550 |
7 | 13363453311052206 |
oct | 1331527403346222 |
9 | 216476736264183 |
10 | 50142603234450 |
11 | 14a823a4346861 |
12 | 5759b80451156 |
13 | 21c957271b18c |
14 | c54cb487ab06 |
15 | 5be4ce1a0050 |
hex | 2d9abc0dcc92 |
50142603234450 has 96 divisors (see below), whose sum is σ = 124951461969600. Its totient is φ = 13307228646400.
The previous prime is 50142603234419. The next prime is 50142603234473. The reversal of 50142603234450 is 5443230624105.
50142603234450 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 50142603234399 and 50142603234408.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 26193526 + ... + 28042574.
It is an arithmetic number, because the mean of its divisors is an integer number (1301577728850).
Almost surely, 250142603234450 is an apocalyptic number.
50142603234450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 50142603234450, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (62475730984800).
50142603234450 is an abundant number, since it is smaller than the sum of its proper divisors (74808858735150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
50142603234450 is a wasteful number, since it uses less digits than its factorization.
50142603234450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1849932 (or 1849927 counting only the distinct ones).
The product of its (nonzero) digits is 345600, while the sum is 39.
Adding to 50142603234450 its reverse (5443230624105), we get a palindrome (55585833858555).
The spelling of 50142603234450 in words is "fifty trillion, one hundred forty-two billion, six hundred three million, two hundred thirty-four thousand, four hundred fifty".
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