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5015305130053 is a prime number
BaseRepresentation
bin100100011111011011101…
…1110110001000001000101
3122202110101020102021211211
41020332313132301001011
51124132321103130203
614355555510331421
71025225636135431
oct110766736610105
918673336367754
105015305130053
111663a84aa7279
1268bbbb659b71
132a4c30bb613a
14134a563179c1
158a6d6209c6d
hex48fb77b1045

5015305130053 has 2 divisors, whose sum is σ = 5015305130054. Its totient is φ = 5015305130052.

The previous prime is 5015305130021. The next prime is 5015305130071. The reversal of 5015305130053 is 3500315035105.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3287991611524 + 1727313518529 = 1813282^2 + 1314273^2 .

It is a cyclic number.

It is not a de Polignac number, because 5015305130053 - 25 = 5015305130021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5015305129997 and 5015305130024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5015305130153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507652565026 + 2507652565027.

It is an arithmetic number, because the mean of its divisors is an integer number (2507652565027).

Almost surely, 25015305130053 is an apocalyptic number.

It is an amenable number.

5015305130053 is a deficient number, since it is larger than the sum of its proper divisors (1).

5015305130053 is an equidigital number, since it uses as much as digits as its factorization.

5015305130053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16875, while the sum is 31.

The spelling of 5015305130053 in words is "five trillion, fifteen billion, three hundred five million, one hundred thirty thousand, fifty-three".