Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …1010111101010001110111 |
3 | 122202110101202022202101002 |
4 | 1020332313322331101313 |
5 | 1124132330001122221 |
6 | 14400000332553515 |
7 | 1025226056015402 |
oct | 110766772752167 |
9 | 18673352282332 |
10 | 5015312520311 |
11 | 1663a89194725 |
12 | 69000202289b |
13 | 2a4c325a2b82 |
14 | 134a572bcd39 |
15 | 8a6d6bb980b |
hex | 48fb7ebd477 |
5015312520311 has 4 divisors (see below), whose sum is σ = 5015338093824. Its totient is φ = 5015286946800.
The previous prime is 5015312520271. The next prime is 5015312520347. The reversal of 5015312520311 is 1130252135105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5015312520311 - 230 = 5014238778487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5015312520371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12490295 + ... + 12885576.
It is an arithmetic number, because the mean of its divisors is an integer number (1253834523456).
Almost surely, 25015312520311 is an apocalyptic number.
5015312520311 is a deficient number, since it is larger than the sum of its proper divisors (25573513).
5015312520311 is a wasteful number, since it uses less digits than its factorization.
5015312520311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25573512.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 5015312520311 its reverse (1130252135105), we get a palindrome (6145564655416).
The spelling of 5015312520311 in words is "five trillion, fifteen billion, three hundred twelve million, five hundred twenty thousand, three hundred eleven".
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