Base | Representation |
---|---|
bin | 100100011111011100111… |
… | …0011100000010101110011 |
3 | 122202110110221210020122111 |
4 | 1020332321303200111303 |
5 | 1124132411043334303 |
6 | 14400003422150151 |
7 | 1025226621432313 |
oct | 110767163402563 |
9 | 18673427706574 |
10 | 5015344121203 |
11 | 1663aa5008969 |
12 | 690010722357 |
13 | 2a4c38cb8720 |
14 | 134a5b587443 |
15 | 8a6d985cb6d |
hex | 48fb9ce0573 |
5015344121203 has 4 divisors (see below), whose sum is σ = 5401139822848. Its totient is φ = 4629548419560.
The previous prime is 5015344121201. The next prime is 5015344121231. The reversal of 5015344121203 is 3021214435105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5015344121203 - 21 = 5015344121201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5015344121201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192897850803 + ... + 192897850828.
It is an arithmetic number, because the mean of its divisors is an integer number (1350284955712).
Almost surely, 25015344121203 is an apocalyptic number.
5015344121203 is a deficient number, since it is larger than the sum of its proper divisors (385795701645).
5015344121203 is a wasteful number, since it uses less digits than its factorization.
5015344121203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 385795701644.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 5015344121203 its reverse (3021214435105), we get a palindrome (8036558556308).
The spelling of 5015344121203 in words is "five trillion, fifteen billion, three hundred forty-four million, one hundred twenty-one thousand, two hundred three".
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