Base | Representation |
---|---|
bin | 101110101110011011… |
… | …111111000011111111 |
3 | 11210111111222122101012 |
4 | 232232123333003333 |
5 | 1310222312241111 |
6 | 35014235105435 |
7 | 3424201160123 |
oct | 565633770377 |
9 | 153444878335 |
10 | 50171212031 |
11 | 1a3063831a6 |
12 | 98822a227b |
13 | 4967387915 |
14 | 25dd37b583 |
15 | 148991448b |
hex | bae6ff0ff |
50171212031 has 2 divisors, whose sum is σ = 50171212032. Its totient is φ = 50171212030.
The previous prime is 50171212001. The next prime is 50171212037. The reversal of 50171212031 is 13021217105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50171212031 - 26 = 50171211967 is a prime.
It is a super-2 number, since 2×501712120312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50171211988 and 50171212006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50171212037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25085606015 + 25085606016.
It is an arithmetic number, because the mean of its divisors is an integer number (25085606016).
Almost surely, 250171212031 is an apocalyptic number.
50171212031 is a deficient number, since it is larger than the sum of its proper divisors (1).
50171212031 is an equidigital number, since it uses as much as digits as its factorization.
50171212031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 23.
Adding to 50171212031 its reverse (13021217105), we get a palindrome (63192429136).
The spelling of 50171212031 in words is "fifty billion, one hundred seventy-one million, two hundred twelve thousand, thirty-one".
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