Base | Representation |
---|---|
bin | 100100100001110101000… |
… | …1100110101010010111111 |
3 | 122202221122212100022102010 |
4 | 1021003222030311102333 |
5 | 1124223340431044203 |
6 | 14402210253102303 |
7 | 1025500312453635 |
oct | 111035214652277 |
9 | 18687585308363 |
10 | 5020451034303 |
11 | 16661857a9301 |
12 | 690bb6a87993 |
13 | 2a557103b5b3 |
14 | 134dc3919355 |
15 | 8a8d7d82303 |
hex | 490ea3354bf |
5020451034303 has 4 divisors (see below), whose sum is σ = 6693934712408. Its totient is φ = 3346967356200.
The previous prime is 5020451034293. The next prime is 5020451034337. The reversal of 5020451034303 is 3034301540205.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5020451034303 - 213 = 5020451026111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5020451034103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 836741839048 + ... + 836741839053.
It is an arithmetic number, because the mean of its divisors is an integer number (1673483678102).
Almost surely, 25020451034303 is an apocalyptic number.
5020451034303 is a deficient number, since it is larger than the sum of its proper divisors (1673483678105).
5020451034303 is a wasteful number, since it uses less digits than its factorization.
5020451034303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1673483678104.
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 5020451034303 its reverse (3034301540205), we get a palindrome (8054752574508).
The spelling of 5020451034303 in words is "five trillion, twenty billion, four hundred fifty-one million, thirty-four thousand, three hundred three".
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