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502144211341 = 4463112512707
BaseRepresentation
bin1110100111010100010…
…00001001100110001101
31210000010021220221020101
413103222020021212031
531211342404230331
61022403141051101
751164413241353
oct7235210114615
91700107827211
10502144211341
11183a5a353193
128139b0b6a91
1338476448296
141a437cdb7d3
15d0dded0061
hex74ea20998d

502144211341 has 4 divisors (see below), whose sum is σ = 502256728512. Its totient is φ = 502031694172.

The previous prime is 502144211339. The next prime is 502144211347. The reversal of 502144211341 is 143112441205.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 502144211341 - 21 = 502144211339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (502144211347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56251891 + ... + 56260816.

It is an arithmetic number, because the mean of its divisors is an integer number (125564182128).

Almost surely, 2502144211341 is an apocalyptic number.

It is an amenable number.

502144211341 is a deficient number, since it is larger than the sum of its proper divisors (112517171).

502144211341 is a wasteful number, since it uses less digits than its factorization.

502144211341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112517170.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 502144211341 its reverse (143112441205), we get a palindrome (645256652546).

The spelling of 502144211341 in words is "five hundred two billion, one hundred forty-four million, two hundred eleven thousand, three hundred forty-one".

Divisors: 1 4463 112512707 502144211341