502500113 has 4 divisors (see below), whose sum is σ = 524347968. Its totient is φ = 480652260.

The previous prime is 502500101. The next prime is 502500133. The reversal of 502500113 is 311005205.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 502500113 - 2⁸ = 502499857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 502500091 and 502500100.

It is not an unprimeable number, because it can be changed into a prime (502500133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10923893 + ... + 10923938.

It is an arithmetic number, because the mean of its divisors is an integer number (131086992).

Almost surely, 2^502500113 is an apocalyptic number.

It is an amenable number.

502500113 is a deficient number, since it is larger than the sum of its proper divisors (21847855).

502500113 is a wasteful number, since it uses less digits than its factorization.

502500113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21847854.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 502500113 is about 22416.5142919233. The cubic root of 502500113 is about 795.0212211679.

Adding to 502500113 its reverse (311005205), we get a palindrome (813505318).

The spelling of 502500113 in words is "five hundred two million, five hundred thousand, one hundred thirteen".