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5025671812159 is a prime number
BaseRepresentation
bin100100100100010000101…
…1000100001010000111111
3122210110010201011022020221
41021020201120201100333
51124320033440442114
614404432312322211
71026043555364425
oct111104130412077
918713121138227
105025671812159
11166841479aa49
126920133a3367
132a5bc384a96b
1413535b04b115
158aae1399524
hex4922162143f

5025671812159 has 2 divisors, whose sum is σ = 5025671812160. Its totient is φ = 5025671812158.

The previous prime is 5025671812103. The next prime is 5025671812177. The reversal of 5025671812159 is 9512181765205.

5025671812159 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5025671812159 - 211 = 5025671810111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5025671812199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512835906079 + 2512835906080.

It is an arithmetic number, because the mean of its divisors is an integer number (2512835906080).

Almost surely, 25025671812159 is an apocalyptic number.

5025671812159 is a deficient number, since it is larger than the sum of its proper divisors (1).

5025671812159 is an equidigital number, since it uses as much as digits as its factorization.

5025671812159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512000, while the sum is 52.

The spelling of 5025671812159 in words is "five trillion, twenty-five billion, six hundred seventy-one million, eight hundred twelve thousand, one hundred fifty-nine".