Base | Representation |
---|---|
bin | 100100100101001100001… |
… | …0110000000110000011111 |
3 | 122210122021210200001001101 |
4 | 1021022120112000300133 |
5 | 1124333130404042143 |
6 | 14405402330053531 |
7 | 1026144201564445 |
oct | 111123026006037 |
9 | 18718253601041 |
10 | 5027667643423 |
11 | 166924934a577 |
12 | 69248b87a2a7 |
13 | 2a61511956c9 |
14 | 1354aa13cb95 |
15 | 8abab6d6b4d |
hex | 49298580c1f |
5027667643423 has 2 divisors, whose sum is σ = 5027667643424. Its totient is φ = 5027667643422.
The previous prime is 5027667643331. The next prime is 5027667643433. The reversal of 5027667643423 is 3243467667205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5027667643423 - 213 = 5027667635231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5027667643433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2513833821711 + 2513833821712.
It is an arithmetic number, because the mean of its divisors is an integer number (2513833821712).
Almost surely, 25027667643423 is an apocalyptic number.
5027667643423 is a deficient number, since it is larger than the sum of its proper divisors (1).
5027667643423 is an equidigital number, since it uses as much as digits as its factorization.
5027667643423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30481920, while the sum is 55.
The spelling of 5027667643423 in words is "five trillion, twenty-seven billion, six hundred sixty-seven million, six hundred forty-three thousand, four hundred twenty-three".
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