Base | Representation |
---|---|
bin | 100100100110000100010… |
… | …1110110001111010000111 |
3 | 122210211011012122110000001 |
4 | 1021030020232301322013 |
5 | 1124401011103400031 |
6 | 14410313403502131 |
7 | 1026242005453441 |
oct | 111141056617207 |
9 | 18724135573001 |
10 | 5029553184391 |
11 | 166a02671a39a |
12 | 692917227947 |
13 | 2a6391a05c18 |
14 | 135608721491 |
15 | 8ac6beda861 |
hex | 49308bb1e87 |
5029553184391 has 2 divisors, whose sum is σ = 5029553184392. Its totient is φ = 5029553184390.
The previous prime is 5029553184389. The next prime is 5029553184419. The reversal of 5029553184391 is 1934813559205.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5029553184391 - 21 = 5029553184389 is a prime.
It is a super-3 number, since 3×50295531843913 (a number of 39 digits) contains 333 as substring.
Together with 5029553184389, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5029553184991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2514776592195 + 2514776592196.
It is an arithmetic number, because the mean of its divisors is an integer number (2514776592196).
Almost surely, 25029553184391 is an apocalyptic number.
5029553184391 is a deficient number, since it is larger than the sum of its proper divisors (1).
5029553184391 is an equidigital number, since it uses as much as digits as its factorization.
5029553184391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832000, while the sum is 55.
The spelling of 5029553184391 in words is "five trillion, twenty-nine billion, five hundred fifty-three million, one hundred eighty-four thousand, three hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •