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50300057471 = 101498020371
BaseRepresentation
bin101110110110000111…
…011111011101111111
311210211111102200002112
4232312013133131333
51311003303314341
635035120444235
73430324301606
oct566607373577
9153744380075
1050300057471
111a372086734
1298b947967b
134987c8aa21
14261251aa3d
151495db5aeb
hexbb61df77f

50300057471 has 4 divisors (see below), whose sum is σ = 50798077944. Its totient is φ = 49802037000.

The previous prime is 50300057461. The next prime is 50300057491. The reversal of 50300057471 is 17475000305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50300057471 - 210 = 50300056447 is a prime.

It is a super-3 number, since 3×503000574713 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50300057461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 249010085 + ... + 249010286.

It is an arithmetic number, because the mean of its divisors is an integer number (12699519486).

Almost surely, 250300057471 is an apocalyptic number.

50300057471 is a deficient number, since it is larger than the sum of its proper divisors (498020473).

50300057471 is a wasteful number, since it uses less digits than its factorization.

50300057471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 498020472.

The product of its (nonzero) digits is 14700, while the sum is 32.

Adding to 50300057471 its reverse (17475000305), we get a palindrome (67775057776).

The spelling of 50300057471 in words is "fifty billion, three hundred million, fifty-seven thousand, four hundred seventy-one".

Divisors: 1 101 498020371 50300057471