Base | Representation |
---|---|
bin | 10110111000000010100110… |
… | …00101111101111100110111 |
3 | 20121010000112210211122202020 |
4 | 23130001103011331330313 |
5 | 23043140144031403101 |
6 | 254553210110244223 |
7 | 13411230164564022 |
oct | 1334012305757467 |
9 | 217100483748666 |
10 | 50304051044151 |
11 | 15034912432863 |
12 | 5785318ab6673 |
13 | 220b861905a18 |
14 | c5ca2c78a1b9 |
15 | 5c37cccc8136 |
hex | 2dc05317df37 |
50304051044151 has 8 divisors (see below), whose sum is σ = 67236058446960. Its totient is φ = 33454038835392.
The previous prime is 50304051044147. The next prime is 50304051044179. The reversal of 50304051044151 is 15144015040305.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 50304051044151 - 22 = 50304051044147 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50304051044101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20498797080 + ... + 20498799533.
It is an arithmetic number, because the mean of its divisors is an integer number (8404507305870).
Almost surely, 250304051044151 is an apocalyptic number.
50304051044151 is a deficient number, since it is larger than the sum of its proper divisors (16932007402809).
50304051044151 is a wasteful number, since it uses less digits than its factorization.
50304051044151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40997597025.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 50304051044151 its reverse (15144015040305), we get a palindrome (65448066084456).
The spelling of 50304051044151 in words is "fifty trillion, three hundred four billion, fifty-one million, forty-four thousand, one hundred fifty-one".
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