Base | Representation |
---|---|
bin | 100100100110111011011… |
… | …1000010111001110100011 |
3 | 122210222220222222212112121 |
4 | 1021031312320113032203 |
5 | 1124413302201042212 |
6 | 14411221021005111 |
7 | 1026335545322002 |
oct | 111156670271643 |
9 | 18728828885477 |
10 | 5031401190307 |
11 | 166a894892608 |
12 | 6931520b3797 |
13 | 2a65c783384b |
14 | 135741d32c39 |
15 | 8ad29377d07 |
hex | 49376e173a3 |
5031401190307 has 2 divisors, whose sum is σ = 5031401190308. Its totient is φ = 5031401190306.
The previous prime is 5031401190281. The next prime is 5031401190371. The reversal of 5031401190307 is 7030911041305.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5031401190307 is a prime.
It is not a weakly prime, because it can be changed into another prime (5031401190397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2515700595153 + 2515700595154.
It is an arithmetic number, because the mean of its divisors is an integer number (2515700595154).
Almost surely, 25031401190307 is an apocalyptic number.
5031401190307 is a deficient number, since it is larger than the sum of its proper divisors (1).
5031401190307 is an equidigital number, since it uses as much as digits as its factorization.
5031401190307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11340, while the sum is 34.
The spelling of 5031401190307 in words is "five trillion, thirty-one billion, four hundred one million, one hundred ninety thousand, three hundred seven".
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