Base | Representation |
---|---|
bin | 100100100110111011011… |
… | …1000111010100100000010 |
3 | 122210222221000021020002011 |
4 | 1021031312320322210002 |
5 | 1124413302220210132 |
6 | 14411221024043134 |
7 | 1026335546463655 |
oct | 111156670724402 |
9 | 18728830236064 |
10 | 5031401335042 |
11 | 166a894981325 |
12 | 6931521634aa |
13 | 2a65c78846a4 |
14 | 135741d6d89c |
15 | 8ad293a5b47 |
hex | 49376e3a902 |
5031401335042 has 8 divisors (see below), whose sum is σ = 7751077732476. Its totient is φ = 2447708757552.
The previous prime is 5031401335031. The next prime is 5031401335067. The reversal of 5031401335042 is 2405331041305.
It can be written as a sum of positive squares in 2 ways, for example, as 5010161478921 + 21239856121 = 2238339^2 + 145739^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×50314013350423 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5031401334995 and 5031401335013.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33995954893 + ... + 33995955040.
Almost surely, 25031401335042 is an apocalyptic number.
5031401335042 is a deficient number, since it is larger than the sum of its proper divisors (2719676397434).
5031401335042 is a wasteful number, since it uses less digits than its factorization.
5031401335042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67991909972.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5031401335042 its reverse (2405331041305), we get a palindrome (7436732376347).
The spelling of 5031401335042 in words is "five trillion, thirty-one billion, four hundred one million, three hundred thirty-five thousand, forty-two".
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