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5031401335042 = 23767991909933
BaseRepresentation
bin100100100110111011011…
…1000111010100100000010
3122210222221000021020002011
41021031312320322210002
51124413302220210132
614411221024043134
71026335546463655
oct111156670724402
918728830236064
105031401335042
11166a894981325
126931521634aa
132a65c78846a4
14135741d6d89c
158ad293a5b47
hex49376e3a902

5031401335042 has 8 divisors (see below), whose sum is σ = 7751077732476. Its totient is φ = 2447708757552.

The previous prime is 5031401335031. The next prime is 5031401335067. The reversal of 5031401335042 is 2405331041305.

It can be written as a sum of positive squares in 2 ways, for example, as 5010161478921 + 21239856121 = 2238339^2 + 145739^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×50314013350423 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5031401334995 and 5031401335013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33995954893 + ... + 33995955040.

Almost surely, 25031401335042 is an apocalyptic number.

5031401335042 is a deficient number, since it is larger than the sum of its proper divisors (2719676397434).

5031401335042 is a wasteful number, since it uses less digits than its factorization.

5031401335042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67991909972.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 5031401335042 its reverse (2405331041305), we get a palindrome (7436732376347).

The spelling of 5031401335042 in words is "five trillion, thirty-one billion, four hundred one million, three hundred thirty-five thousand, forty-two".

Divisors: 1 2 37 74 67991909933 135983819866 2515700667521 5031401335042