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5031401335041 = 31677133778347
BaseRepresentation
bin100100100110111011011…
…1000111010100100000001
3122210222221000021020002010
41021031312320322210001
51124413302220210131
614411221024043133
71026335546463654
oct111156670724401
918728830236063
105031401335041
11166a894981324
126931521634a9
132a65c78846a3
14135741d6d89b
158ad293a5b46
hex49376e3a901

5031401335041 has 4 divisors (see below), whose sum is σ = 6708535113392. Its totient is φ = 3354267556692.

The previous prime is 5031401335031. The next prime is 5031401335067. The reversal of 5031401335041 is 1405331041305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5031401335041 - 210 = 5031401334017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5031401335031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 838566889171 + ... + 838566889176.

It is an arithmetic number, because the mean of its divisors is an integer number (1677133778348).

Almost surely, 25031401335041 is an apocalyptic number.

It is an amenable number.

5031401335041 is a deficient number, since it is larger than the sum of its proper divisors (1677133778351).

5031401335041 is a wasteful number, since it uses less digits than its factorization.

5031401335041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1677133778350.

The product of its (nonzero) digits is 10800, while the sum is 30.

Adding to 5031401335041 its reverse (1405331041305), we get a palindrome (6436732376346).

The spelling of 5031401335041 in words is "five trillion, thirty-one billion, four hundred one million, three hundred thirty-five thousand, forty-one".

Divisors: 1 3 1677133778347 5031401335041