Base | Representation |
---|---|
bin | 101110110111011000… |
… | …101110110101000101 |
3 | 11210212222111122111211 |
4 | 232313120232311011 |
5 | 1311024231312203 |
6 | 35041201131421 |
7 | 3431003311015 |
oct | 566730566505 |
9 | 153788448454 |
10 | 50321354053 |
11 | 1a383102113 |
12 | 9904629b71 |
13 | 498c506359 |
14 | 26152a1c45 |
15 | 1497bc0c6d |
hex | bb762ed45 |
50321354053 has 2 divisors, whose sum is σ = 50321354054. Its totient is φ = 50321354052.
The previous prime is 50321354051. The next prime is 50321354063. The reversal of 50321354053 is 35045312305.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30184892644 + 20136461409 = 173738^2 + 141903^2 .
It is a cyclic number.
It is not a de Polignac number, because 50321354053 - 21 = 50321354051 is a prime.
Together with 50321354051, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50321354051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25160677026 + 25160677027.
It is an arithmetic number, because the mean of its divisors is an integer number (25160677027).
Almost surely, 250321354053 is an apocalyptic number.
It is an amenable number.
50321354053 is a deficient number, since it is larger than the sum of its proper divisors (1).
50321354053 is an equidigital number, since it uses as much as digits as its factorization.
50321354053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 50321354053 its reverse (35045312305), we get a palindrome (85366666358).
The spelling of 50321354053 in words is "fifty billion, three hundred twenty-one million, three hundred fifty-four thousand, fifty-three".
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