Base | Representation |
---|---|
bin | 1001010111111010… |
… | …00100110100100001 |
3 | 110222201100022102022 |
4 | 10223331010310201 |
5 | 40301243214423 |
6 | 2151205431225 |
7 | 235464451421 |
oct | 45375046441 |
9 | 13881308368 |
10 | 5032398113 |
11 | 2152726206 |
12 | b8540b515 |
13 | 622793282 |
14 | 35a4d6481 |
15 | 1e6c05dc8 |
hex | 12bf44d21 |
5032398113 has 4 divisors (see below), whose sum is σ = 5194733568. Its totient is φ = 4870062660.
The previous prime is 5032398103. The next prime is 5032398131. The reversal of 5032398113 is 3118932305.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3118932305 = 5 ⋅623786461.
It is a cyclic number.
It is not a de Polignac number, because 5032398113 - 28 = 5032397857 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5032398103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81167681 + ... + 81167742.
It is an arithmetic number, because the mean of its divisors is an integer number (1298683392).
Almost surely, 25032398113 is an apocalyptic number.
It is an amenable number.
5032398113 is a deficient number, since it is larger than the sum of its proper divisors (162335455).
5032398113 is a wasteful number, since it uses less digits than its factorization.
5032398113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162335454.
The product of its (nonzero) digits is 19440, while the sum is 35.
The square root of 5032398113 is about 70939.3974671339. The cubic root of 5032398113 is about 1713.6613310646.
The spelling of 5032398113 in words is "five billion, thirty-two million, three hundred ninety-eight thousand, one hundred thirteen".
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