Base | Representation |
---|---|
bin | 100100100111011101011… |
… | …1001110010010011011111 |
3 | 122211002212112102001012112 |
4 | 1021032322321302103133 |
5 | 1124423121324222142 |
6 | 14411530145224235 |
7 | 1026406043500631 |
oct | 111167271622337 |
9 | 18732775361175 |
10 | 5032542414047 |
11 | 167031aaa3925 |
12 | 69341033207b |
13 | 2a674a0b9075 |
14 | 13580d722a51 |
15 | 8ad94653382 |
hex | 493bae724df |
5032542414047 has 2 divisors, whose sum is σ = 5032542414048. Its totient is φ = 5032542414046.
The previous prime is 5032542413911. The next prime is 5032542414071. The reversal of 5032542414047 is 7404142452305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5032542414047 - 222 = 5032538219743 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5032542413995 and 5032542414013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5032542414247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516271207023 + 2516271207024.
It is an arithmetic number, because the mean of its divisors is an integer number (2516271207024).
Almost surely, 25032542414047 is an apocalyptic number.
5032542414047 is a deficient number, since it is larger than the sum of its proper divisors (1).
5032542414047 is an equidigital number, since it uses as much as digits as its factorization.
5032542414047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 537600, while the sum is 41.
The spelling of 5032542414047 in words is "five trillion, thirty-two billion, five hundred forty-two million, four hundred fourteen thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •