Base | Representation |
---|---|
bin | 100100100111011101011… |
… | …1001110010010011110111 |
3 | 122211002212112102001020102 |
4 | 1021032322321302103313 |
5 | 1124423121324222241 |
6 | 14411530145224315 |
7 | 1026406043500664 |
oct | 111167271622367 |
9 | 18732775361212 |
10 | 5032542414071 |
11 | 167031aaa3947 |
12 | 69341033209b |
13 | 2a674a0b9093 |
14 | 13580d722a6b |
15 | 8ad9465339b |
hex | 493bae724f7 |
5032542414071 has 2 divisors, whose sum is σ = 5032542414072. Its totient is φ = 5032542414070.
The previous prime is 5032542414047. The next prime is 5032542414113. The reversal of 5032542414071 is 1704142452305.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5032542414071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5032542714071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516271207035 + 2516271207036.
It is an arithmetic number, because the mean of its divisors is an integer number (2516271207036).
Almost surely, 25032542414071 is an apocalyptic number.
5032542414071 is a deficient number, since it is larger than the sum of its proper divisors (1).
5032542414071 is an equidigital number, since it uses as much as digits as its factorization.
5032542414071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 134400, while the sum is 38.
Adding to 5032542414071 its reverse (1704142452305), we get a palindrome (6736684866376).
The spelling of 5032542414071 in words is "five trillion, thirty-two billion, five hundred forty-two million, four hundred fourteen thousand, seventy-one".
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