Base | Representation |
---|---|
bin | 100100100111110100011… |
… | …0101110000011111111111 |
3 | 122211011212020121110022122 |
4 | 1021033220311300133333 |
5 | 1124431211124010030 |
6 | 14412134440033155 |
7 | 1026434122344641 |
oct | 111175065603777 |
9 | 18734766543278 |
10 | 5033313110015 |
11 | 167068603a143 |
12 | 6935a64627bb |
13 | 2a684097b998 |
14 | 135883c20891 |
15 | 8addc13c8e5 |
hex | 493e8d707ff |
5033313110015 has 8 divisors (see below), whose sum is σ = 6248250757440. Its totient is φ = 3887800471072.
The previous prime is 5033313110003. The next prime is 5033313110017. The reversal of 5033313110015 is 5100113133305.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5033313110015 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5033313110017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17356251959 + ... + 17356252248.
It is an arithmetic number, because the mean of its divisors is an integer number (781031344680).
Almost surely, 25033313110015 is an apocalyptic number.
5033313110015 is a deficient number, since it is larger than the sum of its proper divisors (1214937647425).
5033313110015 is a wasteful number, since it uses less digits than its factorization.
5033313110015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34712504241.
The product of its (nonzero) digits is 2025, while the sum is 26.
The spelling of 5033313110015 in words is "five trillion, thirty-three billion, three hundred thirteen million, one hundred ten thousand, fifteen".
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