Base | Representation |
---|---|
bin | 100100100111110101100… |
… | …1011010011001001110011 |
3 | 122211011221222101002112012 |
4 | 1021033223023103021303 |
5 | 1124431301142431121 |
6 | 14412142400153135 |
7 | 1026435106505504 |
oct | 111175313231163 |
9 | 18734858332465 |
10 | 5033352311411 |
11 | 16706a6184796 |
12 | 6935b76087ab |
13 | 2a6848b25b88 |
14 | 135889106bab |
15 | 8ade07d2c5b |
hex | 493eb2d3273 |
5033352311411 has 2 divisors, whose sum is σ = 5033352311412. Its totient is φ = 5033352311410.
The previous prime is 5033352311387. The next prime is 5033352311413. The reversal of 5033352311411 is 1141132533305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5033352311411 - 218 = 5033352049267 is a prime.
Together with 5033352311413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5033352311413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516676155705 + 2516676155706.
It is an arithmetic number, because the mean of its divisors is an integer number (2516676155706).
Almost surely, 25033352311411 is an apocalyptic number.
5033352311411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033352311411 is an equidigital number, since it uses as much as digits as its factorization.
5033352311411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 5033352311411 its reverse (1141132533305), we get a palindrome (6174484844716).
The spelling of 5033352311411 in words is "five trillion, thirty-three billion, three hundred fifty-two million, three hundred eleven thousand, four hundred eleven".
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