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5033540511103 = 13387195423931
BaseRepresentation
bin100100100111111011001…
…1001001110010101111111
3122211012110002111121222011
41021033312121032111333
51124432142332323403
614412213202032051
71026442553254606
oct111176631162577
918735402447864
105033540511103
111670792437a25
1269364a648627
132a6878b0b040
141358a60d6a3d
158ae020aaa6d
hex493f664e57f

5033540511103 has 4 divisors (see below), whose sum is σ = 5420735935048. Its totient is φ = 4646345087160.

The previous prime is 5033540511073. The next prime is 5033540511121. The reversal of 5033540511103 is 3011150453305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5033540511103 - 217 = 5033540380031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5033540511403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193597711953 + ... + 193597711978.

It is an arithmetic number, because the mean of its divisors is an integer number (1355183983762).

Almost surely, 25033540511103 is an apocalyptic number.

5033540511103 is a deficient number, since it is larger than the sum of its proper divisors (387195423945).

5033540511103 is a wasteful number, since it uses less digits than its factorization.

5033540511103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 387195423944.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 5033540511103 its reverse (3011150453305), we get a palindrome (8044690964408).

The spelling of 5033540511103 in words is "five trillion, thirty-three billion, five hundred forty million, five hundred eleven thousand, one hundred three".

Divisors: 1 13 387195423931 5033540511103