Base | Representation |
---|---|
bin | 100100101000001100100… |
… | …0111001111101001001101 |
3 | 122211020221200120011001201 |
4 | 1021100121013033221031 |
5 | 1124434340442003042 |
6 | 14412351050505501 |
7 | 1026463155323251 |
oct | 111203107175115 |
9 | 18736850504051 |
10 | 5034123000397 |
11 | 1670a61215837 |
12 | 693791735291 |
13 | 2a693c6b556a |
14 | 13591d602261 |
15 | 8ae382ba1b7 |
hex | 494191cfa4d |
5034123000397 has 2 divisors, whose sum is σ = 5034123000398. Its totient is φ = 5034123000396.
The previous prime is 5034123000383. The next prime is 5034123000437. The reversal of 5034123000397 is 7930003214305.
It is a happy number.
5034123000397 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4500384630921 + 533738369476 = 2121411^2 + 730574^2 .
It is a cyclic number.
It is not a de Polignac number, because 5034123000397 - 235 = 4999763262029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5034123000197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517061500198 + 2517061500199.
It is an arithmetic number, because the mean of its divisors is an integer number (2517061500199).
Almost surely, 25034123000397 is an apocalyptic number.
It is an amenable number.
5034123000397 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034123000397 is an equidigital number, since it uses as much as digits as its factorization.
5034123000397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 37.
The spelling of 5034123000397 in words is "five trillion, thirty-four billion, one hundred twenty-three million, three hundred ninety-seven", and thus it is an aban number.
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