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5034123000397 is a prime number
BaseRepresentation
bin100100101000001100100…
…0111001111101001001101
3122211020221200120011001201
41021100121013033221031
51124434340442003042
614412351050505501
71026463155323251
oct111203107175115
918736850504051
105034123000397
111670a61215837
12693791735291
132a693c6b556a
1413591d602261
158ae382ba1b7
hex494191cfa4d

5034123000397 has 2 divisors, whose sum is σ = 5034123000398. Its totient is φ = 5034123000396.

The previous prime is 5034123000383. The next prime is 5034123000437. The reversal of 5034123000397 is 7930003214305.

It is a happy number.

5034123000397 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4500384630921 + 533738369476 = 2121411^2 + 730574^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034123000397 - 235 = 4999763262029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5034123000197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517061500198 + 2517061500199.

It is an arithmetic number, because the mean of its divisors is an integer number (2517061500199).

Almost surely, 25034123000397 is an apocalyptic number.

It is an amenable number.

5034123000397 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034123000397 is an equidigital number, since it uses as much as digits as its factorization.

5034123000397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 37.

The spelling of 5034123000397 in words is "five trillion, thirty-four billion, one hundred twenty-three million, three hundred ninety-seven", and thus it is an aban number.