Base | Representation |
---|---|
bin | 100100101000001100101… |
… | …0010101101000001001111 |
3 | 122211020221220012202122111 |
4 | 1021100121102231001033 |
5 | 1124434342224114203 |
6 | 14412351235124451 |
7 | 1026463223004064 |
oct | 111203122550117 |
9 | 18736856182574 |
10 | 5034126004303 |
11 | 1670a62987700 |
12 | 693792743727 |
13 | 2a69401c7916 |
14 | 13591db84c6b |
15 | 8ae386b026d |
hex | 494194ad04f |
5034126004303 has 6 divisors (see below), whose sum is σ = 5533378170152. Its totient is φ = 4576478185620.
The previous prime is 5034126004301. The next prime is 5034126004357. The reversal of 5034126004303 is 3034006214305.
It is not a de Polignac number, because 5034126004303 - 21 = 5034126004301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5034126004301) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 20802173451 + ... + 20802173692.
Almost surely, 25034126004303 is an apocalyptic number.
5034126004303 is a deficient number, since it is larger than the sum of its proper divisors (499252165849).
5034126004303 is a wasteful number, since it uses less digits than its factorization.
5034126004303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41604347165 (or 41604347154 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 31.
The spelling of 5034126004303 in words is "five trillion, thirty-four billion, one hundred twenty-six million, four thousand, three hundred three".
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