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50342005141 is a prime number
BaseRepresentation
bin101110111000100111…
…100000100110010101
311210221102100211110221
4232320213200212111
51311100023131031
635043215514341
73431343661201
oct567047404625
9153842324427
1050342005141
111a39382762a
12990b5289b1
134993886c2c
142617d19b01
1514998eea11
hexbb89e0995

50342005141 has 2 divisors, whose sum is σ = 50342005142. Its totient is φ = 50342005140.

The previous prime is 50342005097. The next prime is 50342005151. The reversal of 50342005141 is 14150024305.

It is a happy number.

50342005141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50341896900 + 108241 = 224370^2 + 329^2 .

It is a cyclic number.

It is not a de Polignac number, because 50342005141 - 211 = 50342003093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50342005151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25171002570 + 25171002571.

It is an arithmetic number, because the mean of its divisors is an integer number (25171002571).

Almost surely, 250342005141 is an apocalyptic number.

It is an amenable number.

50342005141 is a deficient number, since it is larger than the sum of its proper divisors (1).

50342005141 is an equidigital number, since it uses as much as digits as its factorization.

50342005141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 50342005141 its reverse (14150024305), we get a palindrome (64492029446).

The spelling of 50342005141 in words is "fifty billion, three hundred forty-two million, five thousand, one hundred forty-one".