Base | Representation |
---|---|
bin | 101110111000101000… |
… | …100000011011101111 |
3 | 11210221102212010010212 |
4 | 232320220200123233 |
5 | 1311100110012412 |
6 | 35043225253035 |
7 | 3431346130403 |
oct | 567050403357 |
9 | 153842763125 |
10 | 50342266607 |
11 | 1a393996016 |
12 | 990b63417b |
13 | 4993948c49 |
14 | 2617d87103 |
15 | 1499952222 |
hex | bb8a206ef |
50342266607 has 2 divisors, whose sum is σ = 50342266608. Its totient is φ = 50342266606.
The previous prime is 50342266603. The next prime is 50342266609. The reversal of 50342266607 is 70666224305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50342266607 - 22 = 50342266603 is a prime.
Together with 50342266609, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50342266603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25171133303 + 25171133304.
It is an arithmetic number, because the mean of its divisors is an integer number (25171133304).
Almost surely, 250342266607 is an apocalyptic number.
50342266607 is a deficient number, since it is larger than the sum of its proper divisors (1).
50342266607 is an equidigital number, since it uses as much as digits as its factorization.
50342266607 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 50342266607 in words is "fifty billion, three hundred forty-two million, two hundred sixty-six thousand, six hundred seven".
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