Base | Representation |
---|---|
bin | 10011000110000101010… |
… | …101111011101000110001 |
3 | 11122110000121211121102201 |
4 | 103012011111323220301 |
5 | 132444342222104210 |
6 | 2442452313543201 |
7 | 163542410123203 |
oct | 23060525735061 |
9 | 4573017747381 |
10 | 1312202144305 |
11 | 4665579a0878 |
12 | 192391a14b01 |
13 | 969810b7280 |
14 | 47721d86773 |
15 | 242002c553a |
hex | 1318557ba31 |
1312202144305 has 8 divisors (see below), whose sum is σ = 1695768925032. Its totient is φ = 969010814208.
The previous prime is 1312202144251. The next prime is 1312202144413. The reversal of 1312202144305 is 5034412022131.
It can be written as a sum of positive squares in 4 ways, for example, as 95451956209 + 1216750188096 = 308953^2 + 1103064^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1312202144305 - 29 = 1312202143793 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10093862584 + ... + 10093862713.
It is an arithmetic number, because the mean of its divisors is an integer number (211971115629).
Almost surely, 21312202144305 is an apocalyptic number.
It is an amenable number.
1312202144305 is a deficient number, since it is larger than the sum of its proper divisors (383566780727).
1312202144305 is a wasteful number, since it uses less digits than its factorization.
1312202144305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20187725315.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 1312202144305 its reverse (5034412022131), we get a palindrome (6346614166436).
The spelling of 1312202144305 in words is "one trillion, three hundred twelve billion, two hundred two million, one hundred forty-four thousand, three hundred five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •