Base | Representation |
---|---|
bin | 101110111000101111… |
… | …100101001111101011 |
3 | 11210221120100100100001 |
4 | 232320233211033223 |
5 | 1311101043340243 |
6 | 35043333123431 |
7 | 3431400653626 |
oct | 567057451753 |
9 | 153846310301 |
10 | 50344121323 |
11 | 1a394a42541 |
12 | 9910189577 |
13 | 4994148202 |
14 | 261830adbd |
15 | 1499bbba4d |
hex | bb8be53eb |
50344121323 has 2 divisors, whose sum is σ = 50344121324. Its totient is φ = 50344121322.
The previous prime is 50344121309. The next prime is 50344121353. The reversal of 50344121323 is 32312144305.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50344121323 - 217 = 50343990251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50344121291 and 50344121300.
It is not a weakly prime, because it can be changed into another prime (50344121353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25172060661 + 25172060662.
It is an arithmetic number, because the mean of its divisors is an integer number (25172060662).
Almost surely, 250344121323 is an apocalyptic number.
50344121323 is a deficient number, since it is larger than the sum of its proper divisors (1).
50344121323 is an equidigital number, since it uses as much as digits as its factorization.
50344121323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 50344121323 its reverse (32312144305), we get a palindrome (82656265628).
The spelling of 50344121323 in words is "fifty billion, three hundred forty-four million, one hundred twenty-one thousand, three hundred twenty-three".
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