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50344405432511 is a prime number
BaseRepresentation
bin10110111001001101110000…
…11001101111100010111111
320121020212201011201222200112
423130212320121233202333
523044320320242320021
6255023522305020235
713414156204330031
oct1334467031574277
9217225634658615
1050344405432511
111504aa40433043
1257910bb62467b
1322125c3219a28
14c6097a047c51
155c4890963d5b
hex2dc9b866f8bf

50344405432511 has 2 divisors, whose sum is σ = 50344405432512. Its totient is φ = 50344405432510.

The previous prime is 50344405432417. The next prime is 50344405432513. The reversal of 50344405432511 is 11523450444305.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50344405432511 - 222 = 50344401238207 is a prime.

Together with 50344405432513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50344405432513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25172202716255 + 25172202716256.

It is an arithmetic number, because the mean of its divisors is an integer number (25172202716256).

Almost surely, 250344405432511 is an apocalyptic number.

50344405432511 is a deficient number, since it is larger than the sum of its proper divisors (1).

50344405432511 is an equidigital number, since it uses as much as digits as its factorization.

50344405432511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 50344405432511 its reverse (11523450444305), we get a palindrome (61867855876816).

The spelling of 50344405432511 in words is "fifty trillion, three hundred forty-four billion, four hundred five million, four hundred thirty-two thousand, five hundred eleven".