Base | Representation |
---|---|
bin | 100100101000101011110… |
… | …0110111101010000101111 |
3 | 122211100122202111111122012 |
4 | 1021101113212331100233 |
5 | 1124444012401013403 |
6 | 14413043103511435 |
7 | 1026531146405522 |
oct | 111212746752057 |
9 | 18740582444565 |
10 | 5035171501103 |
11 | 167144a055947 |
12 | 693a248b857b |
13 | 2a6a789a4593 |
14 | 1359bc976bb9 |
15 | 8ae9a37bed8 |
hex | 494579bd42f |
5035171501103 has 2 divisors, whose sum is σ = 5035171501104. Its totient is φ = 5035171501102.
The previous prime is 5035171501099. The next prime is 5035171501153. The reversal of 5035171501103 is 3011051715305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5035171501103 - 22 = 5035171501099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5035171501103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5035171501153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517585750551 + 2517585750552.
It is an arithmetic number, because the mean of its divisors is an integer number (2517585750552).
Almost surely, 25035171501103 is an apocalyptic number.
5035171501103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035171501103 is an equidigital number, since it uses as much as digits as its factorization.
5035171501103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7875, while the sum is 32.
The spelling of 5035171501103 in words is "five trillion, thirty-five billion, one hundred seventy-one million, five hundred one thousand, one hundred three".
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